In a three-branch parallel circuit with resistors rated at 4Ω, 5Ω, and 6Ω, the current is highest through which resistor?

In a parallel circuit, the current divides among the branches inversely proportional to the resistance of each resistor. This means that lower resistance allows more current to flow through that branch.

In this scenario, the resistors rated at 4Ω, 5Ω, and 6Ω have different resistances, and the 4Ω resistor has the lowest resistance value. According to Ohm's Law (V = IR), for a given voltage across the entire parallel circuit, the current (I) can be calculated as I = V/R. Therefore, the current through the 4Ω resistor will be higher than the current through the other two resistors since the resistance is lower.

Thus, in this three-branch parallel circuit, the highest current flows through the 4Ω resistor, confirming it as the correct choice.